kotlin中判断字符串

Given a string, we have to count the occurrences of each character.

给定一个字符串，我们必须计算每个字符的出现次数。

Example:

例：

Input:    string = "Hello includehelp how are you !!"    Output:    { =5, a=1, !=2, c=1, d=1, e=4, H=1, h=2, i=1, l=4, n=1, o=3, p=1, r=1, u=2, w=1, y=1}

程序，用于计算Kotlin中字符串中每个字符的出现 (Program to count the occurrences of each character in a string in Kotlin)

In this program, we are using the concept of HashMap, which will contain the individual characters along with its occurrences in the string.

在此程序中，我们使用HashMap的概念，该概念将包含各个字符及其在字符串中的出现。

package com.includehelp.basicimport java.util.*//Main Function, entry Point of Programfun main(args: Array
    
     ) {    //Input Stream    val sc = Scanner(System.`in`)    //input April20.string value    println("Input String : ")    val str: String = sc.nextLine()    val characterHashMap: HashMap
     
       = HashMap
      
       ()    var c: Char    // Scan string and build hash table    for(i in str.indices){        c = str[i]        if (characterHashMap.containsKey(c)) {            // increment count corresponding to c            characterHashMap[c] = characterHashMap[c]!!+1        } else {            characterHashMap[c] = 1        }    }    //print All Occurrence of character    println("All character Count: $characterHashMap")}
      
     
    

Output

输出量

Run 1:Input String :Hello includehelp how are you !!All character Count: { =5, a=1, !=2, c=1, d=1, e=4, H=1, h=2, i=1, l=4, n=1, o=3, p=1, r=1, u=2, w=1, y=1}---Run 2:Input String :Hindustan India android Kotlin Java FlutterAll character Count: { =5, a=5, d=4, e=1, F=1, H=1, i=4, I=1, J=1, K=1, l=2, n=5, o=2, r=2, s=1, t=4, u=2, v=1}

翻译自:

kotlin中判断字符串